Asked by 95

solve 5^y=4^y+3.Round your answer to the nearest tenth.
Answered by Reiny
I will assume you meant
5^y = 4^(y+3) , or else you would have a very messy equation

take log of both sides
log 5^y = log 4^(y+3)
y log5 = (y+3)log4
y log5 = y log4 + 3 log4
ylog5 - ylog4 = 3log4
y(log5 - log4) = 3log4
y = 3log4/(log5-log4)

I will let you do the button-pushing, (I got 18.6)
Answered by 95
I got 6.46
Answered by 95
I did it a second time and got 1.98
Answered by Damon
I get 18.6

95 - Did you see my repair of the sign error I made in your hyperbola problem?
Answered by Damon
note - log 5 - log 4 = log 1.25
Answered by 95
Damon- yes, thank you
Answered by 95
How did you get 18.6? on my calculator I typed in 3*log(4)/log(5)-log(4).Am I doing this wrong? solving it wrong?
Answered by Steve
I see some missing parentheses in the denominator. Or, rather, I don't see them.
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