Asked by Alan
I already did this problem but i decided to check my self since my answer wasn't withthe status quo of the rest of the answers i checked twice and got the same answer. But will someone double check me.
The designers fo the Parthenon, a Greek Temple completed in 432 B.C., utilized the golden ration. The outline of its face fits into a golden rectangle, in which the length varies directly as its height in the ration 1.618 to 1. The length of the temple was about 31m what was the original height of the parthenon.
The answer I came up with was 50.16 m Am i right???
The designers fo the Parthenon, a Greek Temple completed in 432 B.C., utilized the golden ration. The outline of its face fits into a golden rectangle, in which the length varies directly as its height in the ration 1.618 to 1. The length of the temple was about 31m what was the original height of the parthenon.
The answer I came up with was 50.16 m Am i right???
Answers
Answered by
Damon
No, not right, length must be greater than height here.
length = (1.618/1) * height
31 = 1.618 * height
height = 31 / 1.618
length = (1.618/1) * height
31 = 1.618 * height
height = 31 / 1.618
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Anonymous
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Damon
Look at later posts for my reply to Math Lena
Answered by
Damon
5 x^2 + 10 x - 20 = y
first divide everything by 5, the coef of x
x^2 + 2 x - 4 = y/5
now add 4 to both sides
x^2 + 2 x = y/5 +4
now take half the coef of x, square it, and add to both sides
(2/2)^2 =1
so
x^2 + 2 x + 1 = y/5 + 5
NOW the left is
(x+1)^2 = y/5 + 1
symmetry to the right and left of x = -1 where the left is 0
so the x coordinate of the vertex is x = -1
What is y then?
y/5 + 1 = 0
y = -1(5) = -5
so the vertex is at
first divide everything by 5, the coef of x
x^2 + 2 x - 4 = y/5
now add 4 to both sides
x^2 + 2 x = y/5 +4
now take half the coef of x, square it, and add to both sides
(2/2)^2 =1
so
x^2 + 2 x + 1 = y/5 + 5
NOW the left is
(x+1)^2 = y/5 + 1
symmetry to the right and left of x = -1 where the left is 0
so the x coordinate of the vertex is x = -1
What is y then?
y/5 + 1 = 0
y = -1(5) = -5
so the vertex is at
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laquita
How do you solve 2x2+12+5 and that is two to the second power
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hom many linrs of symmetry does a parallelgram hsve
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