Question
A skier of mass 54.6 kg comes down a slope of constant angle 21◦ with the horizontal.
The acceleration of gravity is 9.8 m/s2 .
What is the force on the skier parallel to the slope?
Answer in units of N
The acceleration of gravity is 9.8 m/s2 .
What is the force on the skier parallel to the slope?
Answer in units of N
Answers
Henry
Ws = mg = 54.6 * 9.8 N./kg = 535.1 N. = Weight of skier.
Fs = 535.1 N. @ 21 Deg. = Force of skier.
Fp = 535.1*sin21 = Force parallel to the slope.
Fs = 535.1 N. @ 21 Deg. = Force of skier.
Fp = 535.1*sin21 = Force parallel to the slope.