Asked by S
a skier, mass 61 kg is at the top of a hill and starts down with an initial speed of 5m/s. he does no work on the way down, assume that the hill surface is frictionless. find his speed at the bottom of the hill which is 10m below the top.
Answers
Answered by
bobpursley
PE at top: m g h
Ke at the bottom equals PE at top.
1/2 m v^2=mgh
v=sqrt(2gh)
Ke at the bottom equals PE at top.
1/2 m v^2=mgh
v=sqrt(2gh)
Answered by
S
so 14m/s?
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