Asked by Anon
Is this correct?
1. Find the solution set for x^2/(x+3) < 9/(x+3).
x^2/(x+3) < 9/(x+3)
x^2 < 9
x^2 - 9 < 0
(x-3)(x+3)<0
1. Find the solution set for x^2/(x+3) < 9/(x+3).
x^2/(x+3) < 9/(x+3)
x^2 < 9
x^2 - 9 < 0
(x-3)(x+3)<0
Answers
Answered by
Anonymous
x ^ 2 / ( x + 3 ) < 9 /( x + 3 ) Multiply both sides with ( x + 3 )
x ^ 2 < 9
x < + OR - 3
For :
x = - 3
x + 3 = 0
and
x ^ 2 / ( x + 3 ) = infinity
For that reason solution is x < 3
x ^ 2 < 9
x < + OR - 3
For :
x = - 3
x + 3 = 0
and
x ^ 2 / ( x + 3 ) = infinity
For that reason solution is x < 3