Asked by Raj
I can't figure this one out, the antiderivative of x^-1.
I thought it would be c, but the derivative of c is zero.
I thought it would be c, but the derivative of c is zero.
Answers
Answered by
drwls
That would be the integral of 1/x. It is called the natural logarithm of x, or ln x.
You can't use the rule that the integral of x^n is x^(n+1)/(n+1) on this one, because n = -1 and you get a zero denominator
You can't use the rule that the integral of x^n is x^(n+1)/(n+1) on this one, because n = -1 and you get a zero denominator
Answered by
Anonymous
Integration of 1/x with respect to x is nayural logarithm of x
Answered by
aayush
Integration of 1/x with respect to x is natural logarithm of x
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