Asked by amy
The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the dimensions of the rectangle
Answers
Answered by
Damon
call width w
then length = (w+2)
perimeter = 2 w + 2(w+2)
I think you can get it from there
then length = (w+2)
perimeter = 2 w + 2(w+2)
I think you can get it from there
Answered by
Jason
w = width
l = length
p = perimeter
p = 2w + 2(2w + 2)
34 = 2w + 4w + 4 - distributive property
34 = 6w + 4
30 = 6w - move the 4 to the other side
30/6 = 6w/6
5 = w
to check that
w + w + (2w + 2) + (2w + 2)
5 + 5 + (2(5)+ 2) + (2(5)+ 2)
10 + 12 + 12
=34
l = length
p = perimeter
p = 2w + 2(2w + 2)
34 = 2w + 4w + 4 - distributive property
34 = 6w + 4
30 = 6w - move the 4 to the other side
30/6 = 6w/6
5 = w
to check that
w + w + (2w + 2) + (2w + 2)
5 + 5 + (2(5)+ 2) + (2(5)+ 2)
10 + 12 + 12
=34
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