Asked by Izzy.
I SERIOUSLY need help!
Solve the linear system by using substitution.
x=6-4y
2x-3y=1
Explanation too, please!
Please and thanks!
Solve the linear system by using substitution.
x=6-4y
2x-3y=1
Explanation too, please!
Please and thanks!
Answers
Answered by
Reiny
very very easy
sub x = 6-4y into
2x - 3y = 1
2(6-4y) - 3y = 1
12 - 8y - 3y = 1
-11y = -11
y = 1
then x = 6 - 4(1) = 2
sub x = 6-4y into
2x - 3y = 1
2(6-4y) - 3y = 1
12 - 8y - 3y = 1
-11y = -11
y = 1
then x = 6 - 4(1) = 2
Answered by
Izzy.
Thank you, but:
How did you go from 12-8y-3y to -11y?
How did you go from 12-8y-3y to -11y?
Answered by
Reiny
12 - 8y - 3y = 1
12 - 11y = 1 , that should be clear
12 <b>-12</b> - 11y = 1 <b>-12</b>
-11y = -11
divide by -11
y = 1
12 - 11y = 1 , that should be clear
12 <b>-12</b> - 11y = 1 <b>-12</b>
-11y = -11
divide by -11
y = 1
Answered by
Izzy.
Understood. Thank you.
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