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determine the 100th term of the arithmetic sequence with t7=465 and t13=219

2 answers

t7=465 ---> a+6d=465
t13=219 --> a+12d=219
subtract:
6d = --246
d = -41
in 1st equation: a+6(-41) = 465
a = 711

term(100) = a+99d = ......

you finish it

term(100)= 711+99(-41)
term(100)= -3348

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