Asked by Jenn

B is the midpoint of segment AC and D is the midpoint of segment CE. Solve for x, given BD=3x+5 and AE=4x+20.

Sorry I couldn't get the link for the picture but, the diagram is a picture of a triangle with a C at the top, and A and E on
the bottom angles, with segment BD going through the middle of the triangle.

Thank You ^0^
Answered by Damon
triangle BCD is similar to triangle ACE (side, angle C, side)
AC = 2 BC
therefore AE = 2 BD
therefore
4x+20 = 2 (3x+5) solve that
Answered by Jenn
Thank You So Much! ^0^
Answered by Mr.Sue
What's the answer?
Answered by monte
whats answer
Answered by Keke
What's the answer?
Answered by just tryna get by
BD= 1/2 AE.
So the real equation is 6x+10=4x+20
isolate the variable and you will get your answer.
the answer is x=5
Answered by pickle
1. b
2. a
3. a
4. a
5. c
6. b
7. b
8. c
9. d
10. c
11. midsegment
12. equidstant
13. perpendicluar
14. concurrent lines
Answered by kitty
is pickle right?
Answered by kitty
Is pickle right?
Answered by Anna
No, pickle is not right on all the answers.
Answered by besties <3
1. b
2. b
3. b
4. a
5. b
6. d
7. b
8. a
9. d
10. a

Answered by Not your dad
x=5
Answered by Sakura Line
B is the midpoint of AC and D is the midpoint of CE Solve for x, given BD = 5x + 4 and AE = 4x + 50.
Answered by dabi
AE is divided into two pairs of equal lengths. BD contains one of each pair.

So, BD is half the length of AE.

2(3x+5) = 4x+20
x = 5

Answered by Rick
AE = 2(BD)
4x + 20 = 2(3x + 5)
4x + 20 = 6x + 10
20 = 2x +10
10 = 2x
5 = x
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