Asked by Jenn
B is the midpoint of segment AC and D is the midpoint of segment CE. Solve for x, given BD=3x+5 and AE=4x+20.
Sorry I couldn't get the link for the picture but, the diagram is a picture of a triangle with a C at the top, and A and E on
the bottom angles, with segment BD going through the middle of the triangle.
Thank You ^0^
Sorry I couldn't get the link for the picture but, the diagram is a picture of a triangle with a C at the top, and A and E on
the bottom angles, with segment BD going through the middle of the triangle.
Thank You ^0^
Answers
Answered by
Damon
triangle BCD is similar to triangle ACE (side, angle C, side)
AC = 2 BC
therefore AE = 2 BD
therefore
4x+20 = 2 (3x+5) solve that
AC = 2 BC
therefore AE = 2 BD
therefore
4x+20 = 2 (3x+5) solve that
Answered by
Jenn
Thank You So Much! ^0^
Answered by
Mr.Sue
What's the answer?
Answered by
monte
whats answer
Answered by
Keke
What's the answer?
Answered by
just tryna get by
BD= 1/2 AE.
So the real equation is 6x+10=4x+20
isolate the variable and you will get your answer.
the answer is x=5
So the real equation is 6x+10=4x+20
isolate the variable and you will get your answer.
the answer is x=5
Answered by
pickle
1. b
2. a
3. a
4. a
5. c
6. b
7. b
8. c
9. d
10. c
11. midsegment
12. equidstant
13. perpendicluar
14. concurrent lines
2. a
3. a
4. a
5. c
6. b
7. b
8. c
9. d
10. c
11. midsegment
12. equidstant
13. perpendicluar
14. concurrent lines
Answered by
kitty
is pickle right?
Answered by
kitty
Is pickle right?
Answered by
Anna
No, pickle is not right on all the answers.
Answered by
besties <3
1. b
2. b
3. b
4. a
5. b
6. d
7. b
8. a
9. d
10. a
2. b
3. b
4. a
5. b
6. d
7. b
8. a
9. d
10. a
Answered by
Not your dad
x=5
Answered by
Sakura Line
B is the midpoint of AC and D is the midpoint of CE Solve for x, given BD = 5x + 4 and AE = 4x + 50.
Answered by
dabi
AE is divided into two pairs of equal lengths. BD contains one of each pair.
So, BD is half the length of AE.
2(3x+5) = 4x+20
x = 5
So, BD is half the length of AE.
2(3x+5) = 4x+20
x = 5
Answered by
Rick
AE = 2(BD)
4x + 20 = 2(3x + 5)
4x + 20 = 6x + 10
20 = 2x +10
10 = 2x
5 = x
4x + 20 = 2(3x + 5)
4x + 20 = 6x + 10
20 = 2x +10
10 = 2x
5 = x