B is the midpoint of segment AC and D is the midpoint of segment CE. Solve for x, given BD=3x+5 and AE=4x+20.

Question

B is the midpoint of segment AC and D is the midpoint of segment CE. Solve for x, given BD=3x+5 and AE=4x+20.

Sorry I couldn't get the link for the picture but, the diagram is a picture of a triangle with a C at the top, and A and E on
the bottom angles, with segment BD going through the middle of the triangle.

Thank You ^0^

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15 answers
(click or scroll down)

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Answer 1

Damon answered
12 years ago

triangle BCD is similar to triangle ACE (side, angle C, side)

AC = 2 BC
therefore AE = 2 BD
therefore
4x+20 = 2 (3x+5) solve that

Answer 2

Jenn answered
12 years ago

Thank You So Much! ^0^

Answer 3

Mr.Sue answered
8 years ago

What's the answer?

Answer 4

monte answered
7 years ago

whats answer

Answer 5

Keke answered
7 years ago

What's the answer?

Answer 6

just tryna get by answered
7 years ago

BD= 1/2 AE.

So the real equation is 6x+10=4x+20
isolate the variable and you will get your answer.
the answer is x=5

Answer 7

pickle answered
4 years ago

1. b

2. a
3. a
4. a
5. c
6. b
7. b
8. c
9. d
10. c
11. midsegment
12. equidstant
13. perpendicluar
14. concurrent lines

Answer 8

kitty answered
4 years ago

is pickle right?

Answer 9

kitty answered
4 years ago

Is pickle right?

Answer 10

Anna answered
4 years ago

No, pickle is not right on all the answers.

Answer 11

besties <3 answered
3 years ago

1. b

2. b
3. b
4. a
5. b
6. d
7. b
8. a
9. d
10. a

Answer 12

Not your dad answered
3 years ago

x=5

Answer 13

Sakura Line answered
3 years ago

B is the midpoint of AC and D is the midpoint of CE Solve for x, given BD = 5x + 4 and AE = 4x + 50.

Answer 14

dabi answered
2 years ago

AE is divided into two pairs of equal lengths. BD contains one of each pair.

So, BD is half the length of AE.

2(3x+5) = 4x+20
x = 5

Answer 15

Rick answered
1 year ago

AE = 2(BD)

4x + 20 = 2(3x + 5)
4x + 20 = 6x + 10
20 = 2x +10
10 = 2x
5 = x