Question
write in the form of logA:
log2 + log12
3log5 + 2log3
1/4log81
log36 - log12
log2 + log12
3log5 + 2log3
1/4log81
log36 - log12
Answers
drwls
log 2 + log 12 = log (2*12) = log 24
3log5 + 2log3 = log (5^3*3^2)= log 1125
(1/4)log 81 = log 81^(1/4) = log 3
You do the last one.
Remember log a - log b = log a/b
3log5 + 2log3 = log (5^3*3^2)= log 1125
(1/4)log 81 = log 81^(1/4) = log 3
You do the last one.
Remember log a - log b = log a/b