Asked by Xavier
loga^u-loga^v+3logaw
write as single log
write as single log
Answers
Answered by
oobleck
Are those supposed to be logs base a?
If so, then log_a(u/v * w^3) = log_a(uw^3/v)
If you meant log(a^u), etc., then that would be
log(a^u / a^v * (aw)^3) = log(a^(u+3)*w^3/a^v)
or some other massaged result
If so, then log_a(u/v * w^3) = log_a(uw^3/v)
If you meant log(a^u), etc., then that would be
log(a^u / a^v * (aw)^3) = log(a^(u+3)*w^3/a^v)
or some other massaged result
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