mg(2/3h)=21
solve for h, m, g are given.
What is the initial height big an object if, when dropped from rest , its kinetic energy is 21J 2/3 of the way towards the ground? The mass is 5
2 answers
dropped from h, total energy = m g h
at h/3 total energy = m g h = m g h/3 + 21
(2/3) m g h = 21
(2/3)(5)(9.8) h = 21
solve for h
at h/3 total energy = m g h = m g h/3 + 21
(2/3) m g h = 21
(2/3)(5)(9.8) h = 21
solve for h