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Initial height of (t)=−16t2+32t+43
3 years ago

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Answered by Anonymous
do you mean
h(t) =−16t^2+32t+43
if so then when t= 0 h = 43 feet
and v = 32 ft/second
3 years ago
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Initial height of (t)=−16t2+32t+43

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