Asked by Noor
Find the turning points of y = 3 x 3 + 6 x 2 + 3 x – 1 and determine their nature, also, find the equations of the tangents at these points.
please help me
please help me
Answers
Answered by
Damon
where is the slope zero?
dy/dx = 9 x^2 + 12 x + 3
so
9 x^2 + 12 x + 3 = 0 for turning point
(9x+3)(x+1) = 0
x = -1/3 and x = -1
I will start the x = -1 point. You do the x = -1/3
the slope is 0 at these points so just find y
if x = -1, y = 3(-1)+6(1)+3(-1)-1
= -1
so tangent is y = -1
dy/dx = 9 x^2 + 12 x + 3
so
9 x^2 + 12 x + 3 = 0 for turning point
(9x+3)(x+1) = 0
x = -1/3 and x = -1
I will start the x = -1 point. You do the x = -1/3
the slope is 0 at these points so just find y
if x = -1, y = 3(-1)+6(1)+3(-1)-1
= -1
so tangent is y = -1
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.