Asked by tyron
find the x and y of the turning points of y=(x^3/3)-4x^2+15x-3
Answers
Answered by
Reiny
y' = x^2 - 8x
set that equal to zero for a max/min of y
after factoring, that solves very nicely to
x = 0 and x = 8
sub those x values back into the original to get the matching y's.
set that equal to zero for a max/min of y
after factoring, that solves very nicely to
x = 0 and x = 8
sub those x values back into the original to get the matching y's.
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