Asked by jenny
Driving in a car with a constant velocity of 11.4 m/s you suddenly see an obstacle ahead. Immediately applying the brakes the car slows with an acceleration of 3.80 m/s2.
(i) Calculate the stopping distance of the car, and
(ii) the time taken to stop.
(i) Calculate the stopping distance of the car, and
(ii) the time taken to stop.
Answers
Answered by
drwls
Do step (ii) first.
(ii) Vo = a*t
t = 11.4/3.80 seconds
(i) Stopping distance = (avg. velocity)*t
= (Vo/2)*(Vo/a) = Vo^2/(2 a)
You could do question (i) first using
Vo^2 = 2 a X
but I find it more difficult to remember that formula.
(ii) Vo = a*t
t = 11.4/3.80 seconds
(i) Stopping distance = (avg. velocity)*t
= (Vo/2)*(Vo/a) = Vo^2/(2 a)
You could do question (i) first using
Vo^2 = 2 a X
but I find it more difficult to remember that formula.
Answered by
jenny
thanks alot :D i got 3s for t for part 2!! nd i got 17.1s for part1 is dat correct??
Answered by
drwls
Yes!
Answered by
Henry
post it.
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