Question
A car is traveling at a constant velocity of 21 m/s (about 45 mph). The driver sees a fallen tree lying across the road and hits the brakes after a delay (reaction time) of 245 ms. (1 ms = 10-3 s.)
Calculate the distance the car travels during this 245 ms reaction time period.
Once the brakes are applied, the car slows to a stop with an acceleration of -5.29 m/s2. Calculate the distance the car travels while the brakes are applied.
Calculate the distance the car travels during this 245 ms reaction time period.
Once the brakes are applied, the car slows to a stop with an acceleration of -5.29 m/s2. Calculate the distance the car travels while the brakes are applied.
Answers
Henry
d = Vo*t = 21m/s * 0.245s =
V^2 = Vo^2 + 2a*d.
V = 0.
Vo = 21 m/s.
a = -5.29 m/s.
d = ?.
V^2 = Vo^2 + 2a*d.
V = 0.
Vo = 21 m/s.
a = -5.29 m/s.
d = ?.
mmmm
89