Asked by shyly
pH of 0.3M of sodium acetate
Answers
Answered by
DrBob222
Let's call sodium acetate, NaAc. The Ac^- is hydrolyzed.
.........Ac^- + HOH ==> HAc + OH^-
initial...0.3M...........0......0
change.....-x.............x......x
equil.....0.3-x...........x......x
Kb for acetate = (Kw/Ka) = (HAc)(OH^-)/(Ac^-)
Substitute 1E-14 for Kw.
Ka for acetic acid for Ka.
The ICE chart from above for the others, solve for x which is (OH^-), and convert to pH. Post your work if you get stuck.
.........Ac^- + HOH ==> HAc + OH^-
initial...0.3M...........0......0
change.....-x.............x......x
equil.....0.3-x...........x......x
Kb for acetate = (Kw/Ka) = (HAc)(OH^-)/(Ac^-)
Substitute 1E-14 for Kw.
Ka for acetic acid for Ka.
The ICE chart from above for the others, solve for x which is (OH^-), and convert to pH. Post your work if you get stuck.
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