Asked by 95
What is the transverse axis of the following equation?
25x^2+250x-36y^2-576y=2579
25x^2+250x-36y^2-576y=2579
Answers
Answered by
Steve
25(x^2 + 10x) - 36(y^2 + 16y) = 2579
Complete the squares:
25(x^2 + 10x + 25) - 25*25 - 36(y^2 + 16y + 64) + 36*64 = 2579
25(x+5)^2 - 36(y+8)^2 = 900
How convenient . . .
(x+5)^2/36 - (y+8)^2/25 = 1
Looks like an hyperbola with center at (-5,-8) and horizontal transverse axis
y = -8.
Complete the squares:
25(x^2 + 10x + 25) - 25*25 - 36(y^2 + 16y + 64) + 36*64 = 2579
25(x+5)^2 - 36(y+8)^2 = 900
How convenient . . .
(x+5)^2/36 - (y+8)^2/25 = 1
Looks like an hyperbola with center at (-5,-8) and horizontal transverse axis
y = -8.
Answered by
95
Thank you steve
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