Asked by Cha-Ching
A 47.5g sample of metal is heated to 300.0ºC and placed in a calorimeter containing 75.0g water at 22.0ºC. The final temperature of the system is 40.0ºC. What is the specific heat of the metal? (the specific heat of water is 4.18 J/g ºC)
Thanks for your time helping!
Thanks for your time helping!
Answers
Answered by
Steve
The heat lost by the metal is the heat gained by the water
heat change is mass * delta T * spec heat
Let the spec heat of the metal be z.
47.5(300-40)z = 75(40-22)(4.18)
z = 0.457
Looks like the metal is most likely iron.
heat change is mass * delta T * spec heat
Let the spec heat of the metal be z.
47.5(300-40)z = 75(40-22)(4.18)
z = 0.457
Looks like the metal is most likely iron.
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