A 47.5g sample of metal is heated to 300.0ºC and placed in a calorimeter containing 75.0g water at 22.0ºC. The final temperature of the system is 40.0ºC. What is the specific heat of the metal? (the specific heat of water is 4.18 J/g ºC)

Question

Thanks for your time helping!

Answer 1

The heat lost by the metal is the heat gained by the water

heat change is mass * delta T * spec heat
Let the spec heat of the metal be z.

47.5(300-40)z = 75(40-22)(4.18)
z = 0.457

Looks like the metal is most likely iron.