Question

A player makes 42 out of 60 free throws. He is in a one on one situation.What is the probability he will score 0 points? 1 point? 2 points?

Answer 1

prob (hit) = 42/60 = 7/10
prob(miss) = 3/10

prob 0 points = 3/10 , (only gets one shot, a miss)
prob 1 point = (7/10)(3/10)
= 21/100 , (has to hit first, miss the second
prob 2 points = (7/1)(7/10) = 49/100
(has to make them both

did you notice that 3/10 + 21/100 + 49/100 = 100/100 = 1 ?

Answer 2

When you do a free throw, you get 2 tries
42/60=.7=7/10=70% probability(make)
10/10-7/10=3/10=30% probability (miss)
0 points= 3/10=30%
1 point= 7/10•3/10=21/100=21%
2 points= 7/10•7/10=49/100=49%
To make sure it's in the range of 100 as the whole number add 3/10+21/100+49/100=100/100