Asked by Brittany
Find the horizontal range of a baseball that leaves the bat at an angle of 63 degrees, with the horizontal with an initial velocity of 160 km/hr. discard air resistance
Answers
Answered by
Damon
do the vertical problem
Vi = 160,000/3600 sin 63 = 44.4 m/s sin 63
= 39.6 m/s
how long to reach top where v = 0 ?
v = Vi - 9.8 t
0 = 39.6 - 9.8 t
t = 4.04 seconds to top
that means in the air for 8.08 seconds
now the horizontal problem
goes for 8.08 seconds at 44.4 cos 63 m/s
you can do that
Vi = 160,000/3600 sin 63 = 44.4 m/s sin 63
= 39.6 m/s
how long to reach top where v = 0 ?
v = Vi - 9.8 t
0 = 39.6 - 9.8 t
t = 4.04 seconds to top
that means in the air for 8.08 seconds
now the horizontal problem
goes for 8.08 seconds at 44.4 cos 63 m/s
you can do that
Answered by
Gabby
163 Meters
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