Asked by help

the horizontal range of a projectile is 4 root 3 times of its maximum height. calculate the angle of projection.
Answered by Anonymous
Let 'x' be the angle of projectile with the horizontal.
Then,taking g=10m/s^2:

Given, Hmax=[(usinx)^2]/2g;
R=4(root of 3)x(Hmax);
R=[(u^2)(sin2x)]/g;
Thus,
(u^2)sin2x 4(usinx)^2
-------- = --------------
g (root of 3)2g
Then,upon simplification:
sin2x 2(sinx)(sinx)
----- = -------------
1 (root of 3)

2sinxcosx 2
--------- = -----------
sinxsinx (root of 3)

cosx 1
---- = cotx = -----------
sinx (root of 3)

So,x=60 degrees.
Answered by Heerthana
It is not correct book answer
Answered by Solomon
No satisfaction from the calculation shown
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