Asked by Jessica
A sample of cesium metal reacted completely with water, evolving 47.0 mL of dry H2 at 31°C and 769 mmHg. What is the equation for the reaction?
Answers
Answered by
bobpursley
find the moles of H2.
molesH2=PV/RT
2Cs+ 2H2O>> 2CsOH + H2(g)
I bet you were given the mass of the cesium and you were supposed to verify.
molesH2=PV/RT
2Cs+ 2H2O>> 2CsOH + H2(g)
I bet you were given the mass of the cesium and you were supposed to verify.
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