Asked by Jessica

A sample of cesium metal reacted completely with water, evolving 47.0 mL of dry H2 at 31°C and 769 mmHg. What is the equation for the reaction?
Answered by bobpursley
find the moles of H2.

molesH2=PV/RT

2Cs+ 2H2O>> 2CsOH + H2(g)

I bet you were given the mass of the cesium and you were supposed to verify.