Asked by Melanie
Suppose a sample of Cesium-137 with initial mass of 200 grams decays to a mass of 160 grams voer the course of 10 years.
Find the half-life of Cesium-137 (Round to the nearest year)
How much Cesium-137 is left in the sample after 60 years? Round to the nearest tenth of a gram.
Find the half-life of Cesium-137 (Round to the nearest year)
How much Cesium-137 is left in the sample after 60 years? Round to the nearest tenth of a gram.
Answers
Answered by
drwls
If T is the half life,
(1/2)^(t/T) = 0.16/0.20 = 0.80
where t = 10 yr
(t/T) = 0.3219
T = 31 yr
After 60 yr, the fraction left is
(0.5)^(60/31) = 0.261
Amount left = 200*0.261 = 52.3 g
(1/2)^(t/T) = 0.16/0.20 = 0.80
where t = 10 yr
(t/T) = 0.3219
T = 31 yr
After 60 yr, the fraction left is
(0.5)^(60/31) = 0.261
Amount left = 200*0.261 = 52.3 g
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.