Zinc reacts with HCl to produce ZnCl2 and Hydrogen gas, H2. What volume, in ml of a 1.25 M solution would be required to completely react with 3.27 g of Zn?

Question

Zn(s) + 2 HCl (aq) -------> ZnCl2 + H2

Answer 1

Convert 3.27 g Zn to moles. moles = grams/molar mass.

Using the coefficients in the balanced equation, convert moles Zn to moles HCl.

Then M = moles/L. You know moles and M, solve for L and convert to mL.