Asked by Iain
What are the critical numbers of the function:
f(x)=2x^3-3x^2-36x+14
Thanks
f(x)=2x^3-3x^2-36x+14
Thanks
Answers
Answered by
Reiny
Nothing nice going on here
I tried, x = ±1, ±2, ±7, ±7/2, then gave up
ran it through Wolfram and got this
http://www.wolframalpha.com/input/?i=2x%5E3-3x%5E2-36x%2B14%3D0
I tried, x = ±1, ±2, ±7, ±7/2, then gave up
ran it through Wolfram and got this
http://www.wolframalpha.com/input/?i=2x%5E3-3x%5E2-36x%2B14%3D0
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