Find the critical numbers of the functions.
f(0) = 2sec0 +tan0
on the interval [0,2pi]
2 answers
0 = theta
why not just use x?
f(x) = 2secx+tanx
f' = 2secx tanx + sec^2x
= sec^2(x) (2tanx/secx+1)
= secx^2(x) (2sinx+1)
critical numbers are where
sec^2(x) = 0 -- no solutions there
sinx = -1/2 -- x = 7π/6, 11π/6
f(x) = 2secx+tanx
f' = 2secx tanx + sec^2x
= sec^2(x) (2tanx/secx+1)
= secx^2(x) (2sinx+1)
critical numbers are where
sec^2(x) = 0 -- no solutions there
sinx = -1/2 -- x = 7π/6, 11π/6
1 answer