Asked by Eric

Find the critical numbers of the functions.
f(0) = 2sec0 +tan0

on the interval [0,2pi]

Answers

Answered by Eric
0 = theta
Answered by Steve
why not just use x?

f(x) = 2secx+tanx
f' = 2secx tanx + sec^2x
= sec^2(x) (2tanx/secx+1)
= secx^2(x) (2sinx+1)

critical numbers are where

sec^2(x) = 0 -- no solutions there
sinx = -1/2 -- x = 7π/6, 11π/6
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