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Find all critical numbers:
(x^2+12)(9-x^2)?
1 answer
ok. well first of all, use the product rule: f(x)g'(x) + g(x)f'(x) then set the derivative = to 0
(x^2 +12)(-2x) + (9-x^2)(2x)=0
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2x^3+3x^2-120x
to find the critical numbers I took the derivative which is 6x^2+6x-120 so divide by 6 to simplify x^2+x-20=0 so
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How do you find the critical numbers and the end points of this function:
f(x)=2x^3-3x^2-12x+5 i calculated the critical numbers
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