Asked by ck
find the increasing and decreasing intervals of 4x^3-7x+3
Answers
Answered by
Steve
f = 4x^3 - 7x + 3
= (x-1)(2x-1)(2x+3)
If you've started working with derivatives yet, then you know that where f' > 0, f is increasing
f' = 12x^2 - 7
find where f' >0 and that will tell you where f is increasing.
= (x-1)(2x-1)(2x+3)
If you've started working with derivatives yet, then you know that where f' > 0, f is increasing
f' = 12x^2 - 7
find where f' >0 and that will tell you where f is increasing.
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