Asked by Kaur
                Find increasing and decreasing function for f(x) = (x^3-4)/(x^2)
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                    Answered by
            oobleck
            
    f = (x^3-4)/(x^2) = x - 4/x^2
f' = 1 + 8/x^3
so now just see where f' >0 (increasing) or f'<0 (decreasing)
    
f' = 1 + 8/x^3
so now just see where f' >0 (increasing) or f'<0 (decreasing)
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