Question

The wheel of a car has a radius of 0.390 m. The engine of the car applies a torque of 466 N·m to this wheel, which does not slip against the road surface. Since the wheel does not slip, the road must be applying a force of static friction to the wheel that produces a countertorque. Moreover, the car has a constant velocity, so this countertorque balances the applied torque. What is the magnitude of the static frictional force?

Answer 1

466-fricton*radius=momentinertia*acceleration

but acceleration is zero, so
466=friction*radius.