Asked by Stephanie
A wheel of radius 0.398 m is mounted on a frictionless horizontal axis. The rotational inertia of the wheel about the axis is 0.0576 kg·m2. A massless cord wrapped around the wheel is attached to a 0.790 kg block that slides on a horizontal frictionless surface. If a horizontal force of magnitude P = 3.52 N is applied to the block , what is the angular acceleration of the wheel? Take the clockwise direction to be the negative direction and assume the string does not slip on the wheel.
Answers
Answered by
Elena
ma=P-T
Iε=M=TR
T=P-ma=P-mεR,
T=Iε/R.
P-mεR= Iε/R.
ε=PR/(I+mR²)=
=3.52•0.398/(0.0576+0.790•0.398²)=7.67 rad/s².
Iε=M=TR
T=P-ma=P-mεR,
T=Iε/R.
P-mεR= Iε/R.
ε=PR/(I+mR²)=
=3.52•0.398/(0.0576+0.790•0.398²)=7.67 rad/s².
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