Asked by John
A monatomic ideal gas is compressed adiabatically from a pressure of 1.39 105 Pa and volume of 260 L to a volume of 39.0 L. What is the new pressure of the gas?
Answers
drwls
In an adiabatic compression,
P*V^gamma = constant
where "gamma" is the specific heat ratio, Cp/Cv, which is 5/3 for a monatomic gas.
Therefore,
P2/P1 = [V1/V2)^5/3 = (260/39)^5/3
= 23.62
P2 = 3.28*10^6 Pa
P*V^gamma = constant
where "gamma" is the specific heat ratio, Cp/Cv, which is 5/3 for a monatomic gas.
Therefore,
P2/P1 = [V1/V2)^5/3 = (260/39)^5/3
= 23.62
P2 = 3.28*10^6 Pa
John
Thank you very much