Asked by Riley
An ideal monatomic gas goes from p1 = 180 atm and V1 = 45 m3 to p2 and V2 through an adiabatic process. If p2 = 60 atm, what is V2?
Answers
Answered by
Damon
p1 = 180 atm
V1 = 45 m^3
p2 = 60 attm
V2 = ?
adiabatic
p1 V1^gamma = p2 V2^gamma
gamma = Cp/Cv for ideal monatomic about 1.67
180/60 = (V2/45)^1.67
ln 3 = 1.67 ln(V2/45)
ln (V2/45) = .658
V2/45 = e^.658 = 1.93
V2 = 86.9 m^3
V1 = 45 m^3
p2 = 60 attm
V2 = ?
adiabatic
p1 V1^gamma = p2 V2^gamma
gamma = Cp/Cv for ideal monatomic about 1.67
180/60 = (V2/45)^1.67
ln 3 = 1.67 ln(V2/45)
ln (V2/45) = .658
V2/45 = e^.658 = 1.93
V2 = 86.9 m^3
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