what happens if x = 1. Can you show me how to work out the problem?
2 answers
We need more info. What is the full problem?
I assume you refer to the problem of
(a+b)^2 ≠ a^2 +b^2
now,
(a+b)^2 = a^2 + 2ab + b^2
I have no idea what's so special about 1. Picking 0 for either a or b makes
(a+b)^2 = a^2 +b^2
You want, after all,
a^2 + 2ab + b^2 ≠ a^2 +b^2
2ab ≠ 0
so, as long as neither a nor b is zero, the statement is true.
(a+b)^2 ≠ a^2 +b^2
now,
(a+b)^2 = a^2 + 2ab + b^2
I have no idea what's so special about 1. Picking 0 for either a or b makes
(a+b)^2 = a^2 +b^2
You want, after all,
a^2 + 2ab + b^2 ≠ a^2 +b^2
2ab ≠ 0
so, as long as neither a nor b is zero, the statement is true.
6 answers