Asked by Anonymous
You have a compound that is subject to decay. If you originally started with 80 g of the compound and you ended up with 5 grams 30 days later, what is the half-life of the compound?
Answers
Answered by
DrBob222
I would do it this way.
ln(No/N) = kt
ln(80/5) = k*30
Solve for k, then
k = 0.693/t<sub>1/2</sub>
ln(No/N) = kt
ln(80/5) = k*30
Solve for k, then
k = 0.693/t<sub>1/2</sub>
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