Asked by julie
If 3.65 g of a compound having a molecular weight of 481.93 g mol-1 is dissolved in water to make a final volume of 142 mL, what is the concentration of the solution in mM? Answer to three significant figures.
Answers
Answered by
DrBob222
mols compound = grams/molar mass = ?
M = mols/L solution = mols/0.142 L = ?M. That x 1000 = mM.
M = mols/L solution = mols/0.142 L = ?M. That x 1000 = mM.
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