12) The light velocity in certain liquid is 240000 km / s. Beam falls from air on surface of this liquid under angle 30 . Find refraction angle of the beam.

Answer 1

Since the light velocity in the liquid is 240,000 km/s, the refractive index is
N = c/v = 300,000/240,000 = 1.25.

The angle in incidence is
Ai = 30 degrees.

The angle of refraction (Ar) is given by Snell's Law:

N*sinAr = sinAi = 0.50
sinAr = 0.40
Sr = 23.6 degrees