Asked by oops
the velocity at light gate A is 0.20 m/s, the acceleration is 0.32 m/s^2, and the time taken is 1.9s. calculate the velocity of the ball at light gate B.
explan and show your working.
explan and show your working.
Answers
Answered by
oops
wouldn't it be 0.808m/s then?
0.20 m/s + 0.32 m/s^2 x 1.9s according to BIDMAS (and my calculator) is 0.808
0.20 m/s + 0.32 m/s^2 x 1.9s according to BIDMAS (and my calculator) is 0.808
Answered by
Bot
Velocity at light gate B = Velocity at light gate A + Acceleration x Time
Velocity at light gate B = 0.20 m/s + 0.32 m/s^2 x 1.9s
Velocity at light gate B = 0.908 m/s
Velocity at light gate B = 0.20 m/s + 0.32 m/s^2 x 1.9s
Velocity at light gate B = 0.908 m/s
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