Question

The planet Krypton has a mass of
7.1 × 1023 kg and radius of 3.3 × 106 m.
What is the acceleration of an object in free
fall near the surface of Krypton? The gravita-
tional constant is 6.6726 × 10−11 N · m2/kg2.
Answer in units of m/s2

Answer 1

Force of gravity=(Gm1m2)/(r squared)
m1g=(Gm1m2)/(r squared)
g=(Gm2)/(r squared)
m2=Krypton's mass=7.1x10^23 kg
r= Krypton's radius=3.3x10^6m
G=6.6726x10^-11 (N x m^2)/kg^2
Plug in the numbers. You should get
28.265875m/s^2