Divide: (20b^(3)+17b^(2)+18b+43)÷(4b+5)

3 answers

Given that 5 does not divide 43, will will have a remainder. Doing the long division, we get

5b^2 - 2b + 7 + 8/(4b+5)
Thank you.
Hope that helped. It's hard to show the work of long division when the browser does its own formatting of the text.
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