Asked by Allison Anderson
solve for x 4x(x-8)-5x(x-7)=-4
Answers
Answered by
Steve
4x^2 - 32x - 5x^2 + 35x = -4
x^2 - 3x - 4 = 0
(x-4)(x+1) = 0
x = 4 or -1
x^2 - 3x - 4 = 0
(x-4)(x+1) = 0
x = 4 or -1
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