Asked by debra rees
Diameter of an electric cable is normally distributed with a mean f 0.8 with a standard deviation of 0.01. What is the probability that the diameter will exceed 0.83?
Answers
Answered by
Reiny
The beauty of the following applet is that you don't even have to convert to z-scores
http://davidmlane.com/hyperstat/z_table.html
Just enter .8 as the mean and .01 as the standard deviation.
Click on "above" and enter .83 to get
.001350
or
you could find the z-scores.
it it easy to see that .83 would be exactly 3 SD's from the mean of 0,
if you enter mean=0, SD = 1, "above" =3 you will get the same result
Or
go to whatever chart you are using, and look up under a score of 3.0, your result should also be .00135
http://davidmlane.com/hyperstat/z_table.html
Just enter .8 as the mean and .01 as the standard deviation.
Click on "above" and enter .83 to get
.001350
or
you could find the z-scores.
it it easy to see that .83 would be exactly 3 SD's from the mean of 0,
if you enter mean=0, SD = 1, "above" =3 you will get the same result
Or
go to whatever chart you are using, and look up under a score of 3.0, your result should also be .00135
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