Asked by Elle
The cable of an elevator of mass M = 1020 kg snaps when the elevator is at rest at one of the floors of a skyscraper. At this point the elevator is a distance d = 18.4 m above a cushioning spring whose spring constant is k = 6500 N/m. A safety device clamps the elevator against the guide rails so that a constant frictional force of f = 6678 N opposes the motion of the elevator. Find the maximum distance by which the cushioning spring will be compressed.
This is what I did but the answer was wrong!:
Wtotal = (mg- f) 18.4m
Wtotal = 1/2 kx^2
This is what I did but the answer was wrong!:
Wtotal = (mg- f) 18.4m
Wtotal = 1/2 kx^2
Answers
Answered by
Quidditch
Your approach looks OK.
Check for any errors in copying the problem or any math errors.
Check for any errors in copying the problem or any math errors.
Answered by
Elle
Wtotal = [(1020)(9.8)-6678] 18.4
= 61051.2J
61051.2J = 1/2 (6500)x^2
x = 4.33m
STill wrong :( Help
= 61051.2J
61051.2J = 1/2 (6500)x^2
x = 4.33m
STill wrong :( Help
Answered by
Quidditch
The displacement of the safety spring has to be considered in the total potential energy of the elevator car.
Answered by
Elle
Um are you saying
Wtotal = [(1020)(9.8)-6678] (18.4+x) ?..
In that case, I did the quadratic and got x=17.33m, but still wrong answer :( argg
Wtotal = [(1020)(9.8)-6678] (18.4+x) ?..
In that case, I did the quadratic and got x=17.33m, but still wrong answer :( argg
Answered by
Quidditch
For the roots of the quadratic I got
+4.875
-3.854
+4.875
-3.854
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