Question
complete combustion of a 0.0100mol sample of hydrocarbon, CxHy, gives 1.344 L of CO2 at STP and 0.720 g of H2O.
a. what is the molecular formula of hydrocarbon?
b. what is the empirical formula of hydrocarbon?..
a. what is the molecular formula of hydrocarbon?
b. what is the empirical formula of hydrocarbon?..
Answers
1.344 L CO2 for 0.0100 mol sample would have evolved 134.4 L CO2 for a 1.00 mole sample. 134.4/44 = 3.05 moles C/mole unknown. So the formula is C3 H something.
0.720 g H2O for 0.01 mole would have evolved 72.0 g for a 1.00 mole sample and 72.0/18 = 3.99 moles H2O or that x 2 = 7.99 moles H atoms. So the molecular formula is C3H8 (3.05 rounds to 3.00 and 7.99 rounds to 8.00).
0.720 g H2O for 0.01 mole would have evolved 72.0 g for a 1.00 mole sample and 72.0/18 = 3.99 moles H2O or that x 2 = 7.99 moles H atoms. So the molecular formula is C3H8 (3.05 rounds to 3.00 and 7.99 rounds to 8.00).
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