Asked by Eric

Complete combustion of a 0.40-mol sample of a hydrocarbon, CxHy, gives 2.40 mol of CO2 and 1.60 mol of H2O. The molecular formula of the original hydrocarbon is
Group of answer choices

C2H8.

C6H8.

C9H16.

C5H5.

C4H7.
Answered by R_scott
the product has 2.4 moles of C and 3.2 moles of H
... this from a 0.40 moles sample that was combusted

look at the mole ratios of the possible answers
Answered by ئب
ؤ2ا2
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