Since you do not specify, I will assume 60 degrees from horizontal
tan 60 = mg/(m v^2/r)
v^2/r = g/tan 60
v^2 = g r/tan 60
v = sqrt(981/tan 60)
v = 23.8 m/s
(637) A cyclist is riding on a horizontal frozen meadow. He is turning so that he is tilted at an angle of 60°. Radius of curvature of the bend is 100m. What is the maximum speed of the cyclist?
Thank you for your time!
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1 answer