Question

find the veretx, the line of symmetry, and the maximuym or minimum value of
f(x)=-(x-8)^2-2

Help

Answer 1

Look at the function.

(x-8)^2 is always positive. Its least value is where x=8, when it is zero.

However, you have -(x-8)^2, so it has a maximum value at x = 8.

So, the vertex is obviously where x=8. That means that the vertex is (8,f(8)) = (8,-2)

The y-value at the vertex is the maximum or minimum value.